Other way is reaction of hydrochloric acid and aqueous sodium hydroxide reaction. One way is reaction of sodium and chlorine gas. I have studied several reactions possible for sodium chloride production. I want to prepare sodium chloride by a reaction. This is a composition reaction because two compounds combine together and produce one compound as product. When sodium reacts with clorine gas, sodium chloride (NaCl) is given as the product. Qualitative analysis testings for sodium ion and chloride ion.Īsk your chemistry questions and find the answers the product metal sodium reacts with clorine gas in a composition reaction If you mix considerable amount of chlorine gas and sodium, you can see the reaction is being occurred beacause reaction beaker will be red colour due to emission of large heat. Because of this, to react with 2 mol of chlorine gas, 4 mol of sodium is required and there is 4 mol at the beginning of the reaction. Now you now we have to find out how much sodium chloride is produced in this question.Īccording to the stoichiometry, to react with 1 mol of chlorine gas, 2 mol of sodium is required. Now you know, released heat depends on the formed sodium chloride amount. If 2 mol of sodium chloride is formed, 411.120 * 2 kJ is released to the outside. How much energy is released from the reaction? Standard enthalpy of formation of sodium chloride = -411.120 kJ/molĭefinition of Standard enthalpy of formation of sodium chloride: When 1 mol of sodium chloride is formed, 411.120 kJ is released to the outside. You are going to mix 4 mol of sodium and 2 mol of chlorine gas. Standard enthalpy of reaction = -411.12 kJĮntropy of the reaction (298 0C) = 72.10 J/(K mol) Reaction of sodium and chlorine is an exothermic one (heat is released from the reaction).Įnthalpy of the reaction is taken as enthalpy of formation of two moles sodium chloride. Likes to remove its outer electrons and chlorine desired to take electrons from outside. This reaction occurs in a rapid rate because both reactants are very reactive. The solid reactant, sodium reacts with green-yellow gaseous chlorine and produce solid sodium chloride So they are sameĪnd cancel out each other. Oxidation number difference of sodium is two and for chlorine it is two. Next, find oxidation number differences of oxidized atoms (sodium to sodium ion) and reduced atoms (chlorine Therefore, make two sodium atoms in the left. Then there are two sodium atoms in the right side of the reaction, but only one in the left In left side, there are two chlorine atoms. Write oxidation numbers if each atom close to the atoms.Ĭheck the number of atoms of oxidized and reduced in the reaction (left and right side) and balance them if Chlorine is reduced to -1 oxidation stateįrom 0 oxidation state. Oxidation state and to +1 oxidation state. Good example to start your redox reaction balancing. This is a so easy redox reaction to balance and if you are beginner to balancing equations, this is also an How to balance the reaction from redox method? But it is useful in balancing large redox equations. It is easy to balance this reaction by inspection method than redox method. Two moles of chlorine gas reacts with one mole of sodium to produce two moles of sodium chloride. Balanced chemical equation of Na + Cl 2 reaction Sodium readily eliminate its last shell electrons become Na + cation and chlorine accepts thatĮlectron to form Cl - anion. Usually, metals like to eliminate electrons and non-metals such as halogens like to accept electrons. We know sodium is a very active metal and chlorine is also a very reactive non-metal. Sodium is oxidized to sodium cation (Na +) and chlorine gas is reduced to chloride anions (Cl -). Sodium, a very reactive metal which reacts with chlorine gas and produces sodium chloride, the neutral salt. Sodium and Chlorine Gas Reaction | Na + Cl 2